Given an array S of n integers, are there elements a, b, c in S such that a + b + c = 0? Find all unique triplets in the array which gives the sum of zero.
Note: The solution set must not contain duplicate triplets.
For example, given array S = [-1, 0, 1, 2, -1, -4], A solution set is: [ [-1, 0, 1], [-1, -1, 2] ]
Solution:-
public class Solution {
public List<List<Integer>> threeSum(int[] nums) {
Arrays.sort(nums);
List<List<Integer>> res = new ArrayList<List<Integer>>();
Map<String , Integer> map = new HashMap<String, Integer>();
HashSet<List<Integer>> set = new HashSet<List<Integer>>();
for(int i = 0 ; i < nums.length -2 ; i++){
int start = i + 1 ;
int end = nums.length - 1;
while(start < end){
if(nums[i] + nums[start]+ nums[end] == 0){
List<Integer> temp = new ArrayList<Integer>();
temp.add(nums[i]);
temp.add(nums[start]);
temp.add(nums[end]);
set.add(temp);
start++;
end--;
}
else{
if(nums[i] + nums[start]+ nums[end] < 0){
start++;
}
else{
end--;
}
}
}
}
res.addAll(set);
return res;
}
}
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