Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
Note:
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initialized in nums1 and nums2 are m and n respectively.
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initialized in nums1 and nums2 are m and n respectively.
Solution:-
class Solution {
public void merge(int[] nums1, int m, int[] nums2, int n) {
int [] ret = new int[m+n];
int k = 0 , i = 0 , j = 0;
while( i < m && j < n){
if(nums1[i] <= nums2[j]){
ret[k] = nums1[i];
i++;
}
else{
ret[k] = nums2[j];
j++;
}
k++;
}
if( i == m && j < n){
for(int item = j ; item < n ; item++ ){
ret[k] = nums2[item];
System.out.println(ret[k] + " "+ nums2[item]);
k++;
}
}
if( j == n && i < m){
for(int item = i ; item < m ; item++ ){
ret[k] = nums1[item];
k++;
}
}
for(int l = 0 ; l < ret.length ; l++){
nums1[l] = ret[l];
}
}
}
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